This week we have been learning about inscribed circles, arcs, and chords. In this problem we are finding mA and how we well do this is. First we are going to look for which one equals to 180 besides mA. The only one that equals 180 is (5y+8). When solving this problem you would do 6y-2=5y+8 subtract 5 from both sides and add 2 on both sides you always change the sides. For example if 5 was (-5) you would change it to (+5) same for an negative sign you would change it to a (+) but back to solving our problem. y=10 but we are not looking for y we are looking for mA so plug in mA=6(10)-2,mA=60-2, mA=58 and. That’s how you solve this problem.

In this problem we are finding the mG and how we well do this is the same way we did the first one look for one of the arcs that equals 180. The one that equals 180 is 11x+8 now we plug in. 11x+8=8x+1=180 add 11x+8=19 that’s how I got 19x. Now you do 19x+9 I got 9 for 8x+1=9 and it also =180. Now subtract 180-9= 171 and then change (+9) to (-9). Then subtract (-9) from both sides and that equals x=9. Now you plug in mG=8(9)+1,72+1, mG=73. That’s how you work this problem out.

This problem we are finding x if M=P. But we are not solving it like we did the first two problems this one is less more work. We are still doing the same thing like we do the other  problems.We just are not doing the plug in the arc back in and multiplying. SO, first you plug in 6x=2x+24 or you can do 2x+24=6x remember to change (+2) to (-2) and. Subtract both sides by 2 then divide by. 6x/24=6 and that’s how you solve this problem you just have to read the problems carefully then you can know what you are doing.